14x^2-9x-20=-2

Solution for 14x^2-9x-20=-2 equation:

14x^2-9x-20=-2

We move all terms to the left:

14x^2-9x-20-(-2)=0

We add all the numbers together, and all the variables

14x^2-9x-18=0

a = 14; b = -9; c = -18;
Δ = b2-4ac
Δ = -92-4·14·(-18)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-33}{2*14}=\frac{-24}{28}
=-6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+33}{2*14}=\frac{42}{28}
=1+1/2
$